Answer:
38.3 g
Explanation:
8) What mass of chlorine reacts with 20.0 g of iron to form iron(III) chloride?
first write, then balance the equation
Fe + Cl2-------------> FeCl3
2Fe + 3Cl2----------> 2FeCl3
2 moles of Fe require 3 moles of Cl2
the atomic mass of Fe is 56
20/56= 0.36 moles of Fe
this requires o.36 X 3/2 = 0.54 moles of Cl2
Cl2 has a molar mass of 35.5 X 2=71
1 mole of Cl2 is 71g
0.54 moles is 0.54 X 71 g= 38.3 g
