Respuesta :

discipulus

Answer:

[tex]x - 2y = 8 ...(1)\\ 3x - 2y = 0 \rightarrow \: 2y = 3x...(2) \\ sub \: (2)in \: (1) \\ x - 3x = 8 \\ - 2x = 8 \\ x = - \frac{8}{2} \\ x = - 4 \\ 2y = 3( - 4) \\ 2y = - 12 \\ y = - \frac{12}{2} \\ y = - 6[/tex]