jochosanchez1313 jochosanchez1313
  • 14-10-2021
  • Physics
contestada

Find the distance from a point charge q=100nC where the field intensity is equal to E=6kN/C. please include description of the result

Respuesta :

santy1508cech santy1508cech
  • 14-10-2021

Answer: 0.3872m

Explanation:

q= 100nC -->  100x10^-9 C

k= 9x10^9 Nm^2/C^2

E= 6kN/C --> 600 N/C

r=?

[tex]E= K\frac{q}{r^{2} }[/tex] --> [tex]r=\sqrt{\frac{kq}{E} }[/tex] Despejas "r"

Resuelves

[tex]r=\sqrt{\frac{(9x10^9 Nm^2/C^2)(100x10x^{-9} C)}{6000N/C} }[/tex]  (la x es por, no es una variable)

r= 0.3872983346m

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