Answer:
t = 4 s
Step-by-step explanation
We can infer the origin from the t⁰ term of the quadratic as being 192 feet above the ground. Initial velocity is 16 ft/s from the t¹ term, gravity is -32 ft/s² from the t² term
0 = -16t² + 16t + 192
0 = -t² + t + 12
0 = t² - t - 12
0 = (t - 4)(t + 3)
so either
t - 4 = 0
t = 4 s
or
t + 3 = 0
t = -3 s which we ignore as it occurs before the ball is released.
