Answer:
Step-by-step explanation:
because -3 is a zero, so x=-3
(k-1)(-3)²+k(-3)+1=0
9(k-1)-3k+1=0
9k-9-3k+1=0
6k=8
3k=4
k=4/3
(B)
∵ x=-1 is a zero of p(x)=kx²-4x+k
so k(-1)²-4(-1)+(-1)=0
k+4-1=0
k=-3
