dddamaris44 dddamaris44
  • 11-09-2021
  • Mathematics
contestada

I need help please!!!

I need help please class=

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Аноним Аноним
  • 11-09-2021

[tex]\\ \bull\tt\dashrightarrow f(x)=6^x[/tex]

[tex]\\ \bull\tt\dashrightarrow f(-2)=6^{-2}=\dfrac{1}{6^2}=\dfrac{1}{36}[/tex]

[tex]\\ \bull\tt\dashrightarrow f(-1)=6^{-1}=\dfrac{1}{6}[/tex]

[tex]\\ \bull\tt\dashrightarrow f(0)=6^0=1[/tex]

[tex]\\ \bull\tt\dashrightarrow f(1)=6^1=6[/tex]

[tex]\\ \bull\tt\dashrightarrow f(2)=6^2=36[/tex]

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