Answer:
from the pic:
[tex]empirical \: formular : \: \: C _{2}H _{3}O _{2}[/tex]
since molar mass is 118.084 g/mol;
[tex](C _{2}H _{3}O _{2}) _{n} = 118.084 \\ C _{2n}H _{3n}O _{2n} = 118.084 \\(12 \times 2) _{n} + (1 \times 3) _{n} + (16 \times2 ) _{n} = 118.084 \\ 24_{n} + 3_{n} + 32_{n} = 118.084 \\ 59_{n} = 118.084 \\ n = 2[/tex]
[tex]{ \boxed{ \bf{molecular \: formular : \: C _{4}H _{6}O _{4}}}}[/tex]
It is an aldehyde with structure ( second pic )
