Answer:
[tex]y = 3x^2-24x+40[/tex]
Step-by-step explanation:
Hi there!
Standard form: [tex]y=ax^2+bx+c[/tex]
[tex]y = 3(x-4)^2-8[/tex]
Solve [tex](x-4)^2[/tex]
[tex]y = 3(x^2-8x+16)-8[/tex]
Multiply 3 by the parentheses
[tex]y = 3x^2-24x+48-8\\y = 3x^2-24x+40[/tex]
I hope this helps!
