[tex]\boxed{\large{\bold{\blue{ANSWER~:) }}}}[/tex]
Here given
- one angle =26u
- 2nd angle =41°
- 3rd angle=u+31°
.we know that
[tex]\sf{ sum~ of~ 3 ~angles ~of~ a ~triangle~ is ~180° }[/tex]
According to the question,
- 26u+41+u+31=180
- 27u+72=180
- 27u=180-72
- 27u=108
- u=108/27
- u=4°
Therefore:-
The value of u is 4°
