Answer:
[tex]16[/tex]
Step-by-step explanation:
The discriminant of a quadratic in standard form [tex]ax^2+bx+c[/tex] is given by [tex]b^2-4ac[/tex].
The quadratic [tex]-3=-x^2+2x[/tex] in standard form is [tex]-x^2+2x+3[/tex]. Thus, we can assign the following values:
- [tex]a[/tex] of -1
- [tex]b[/tex] of 2
- [tex]c[/tex] of 3
Therefore, the discriminant of this quadratic is [tex]2^2-4(-1)(3)=4+12=\boxed{16}[/tex]
