Answer:
[tex]I=1.9A[/tex]
Explanation:
From the question we are told that:
Meter distance [tex]d=0.0525[/tex]
Magnetic field [tex]B=7.14*19^{-6}T[/tex]
Generally the equation for Magnetic field B is mathematically given by
[tex]B =\frac{\mu *I }{2* \pi r}[/tex]
[tex]7.14*19^{-6}T =\frac{ 1.26 *10^{-6} *I }{2* 3.142*0.0525}[/tex]
Where
Constant[tex]\mu=1.26 *10^{-6}[/tex]
[tex]I=1.9A[/tex]
Therefore
The Current through the wire is
[tex]I=1.9A[/tex]
