Answer:
P1.H.x²+y²=34
centre[h,k]=(0,0)
point=[3,5]
now
radius=[tex]\sqrt{(0-3)²+(0-5)²}=\sqrt{34}[/tex]
now
equation of a circle is;
(x-h)²+(y-k)²=[tex]\sqrt{34}²[/tex]
x²+y²=34
P:2I.(x-6)²+(y+7)²=121
centre[h,k]=(6,-7)
diameter=22
radius[r]=22/2=11
now
equation of a circle is;
(x-h)²+(y-k)²=r²
(x-6)²+(y+7)²=11²
(x-6)²+(y+7)²=121
