Answer:
82gS
Explanation:
2 Fe + 3 S → Fe2S3
↓ ↑
mol → mol
Fe S
[tex]\frac{95 g Fe }{} \frac{1 mol Fe }{55.85 g Fe } \frac{3 mol S }{2 mol Fe } \frac{32.07 g S}{1 mol S} = 82 g S[/tex]
