jaylacansino16 jaylacansino16
  • 15-04-2021
  • Mathematics
contestada

2
ED and CD are tangent to oo at D. The diameter of the circle is 48 cm. ED =32 cm. Find the length of OD
E
C
OD=
cm

2 ED and CD are tangent to oo at D The diameter of the circle is 48 cm ED 32 cm Find the length of OD E C OD cm class=

Respuesta :

Аноним Аноним
  • 15-04-2021

Answer:

[tex]od = 8 \sqrt{7} [/tex]

Step-by-step explanation:

Apply pythagorean theorem.

[tex]eo {}^{2} + od {}^{2} = ed {}^{2} [/tex]

EO is the radius so it is half of the diameter.

EO=24. ED is the hypotenuse.

[tex]24 {}^{2} + od {}^{2} = 32 {}^{2} [/tex]

[tex]576 + od {}^{2} = 1024[/tex]

[tex]od {}^{2} = 448[/tex]

[tex]od = 8 \sqrt{7} [/tex]

s

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