Cosmos
Cosmos Cosmos
  • 12-04-2021
  • Mathematics
contestada

Could someone help me, please?

Could someone help me please class=

Respuesta :

jacinta57
jacinta57 jacinta57
  • 12-04-2021

Answer:

33°

Step-by-step explanation:

<ACD =90-33 =57°

<DCB=<ACB - <ACD

=90° -57 =33°

In triangle ACD the only angle that has not been found is <ACD so you find it by adding 90+33 and subtracting from 180° to get 57°. <ACB =90° and <ACD = 57° ,the angle in question is<DCB which is part of< ACB. So to get <DCB you do 90°-57°=33°.

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jimmy11143
jimmy11143 jimmy11143
  • 12-04-2021

B = 180 - 90 - 33 = 57°

C in DCB tringle = 180 - 90 - 57 = 33°

So C in DCB triangle = 33°

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