Answer:
[tex]\frac{16y-5}{18y^{2} }[/tex]
Step-by-step explanation:
[tex]\frac{8}{9y} -\frac{5}{18y^{2} }[/tex], multiply the first fraction by 2y/2y to get a common denominator
so [tex]\frac{16y}{18y^{2} } -\frac{5}{18y^{2} }[/tex] then simplify [tex]\frac{16y-5}{18y^{2} }[/tex]
