14-03-2021
Mathematics

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14-03-2021

Step-by-step explanation:

[tex] {f}^{ - 1} (x) = x \: value[/tex]

[tex]f(x) = \sqrt[4]{x} + 6 \\ [/tex]

[tex]x - 6 = \sqrt[4]{x} [/tex]

[tex] {(x - 6)}^{4} = x[/tex]

[tex] {f}^{ - 1}(x) = {(x - 6)}^{4} [/tex]

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