hahdbehzhsHelo540 hahdbehzhsHelo540
  • 13-03-2021
  • Mathematics
contestada

In ΔBCD, the measure of ∠D=90°, the measure of ∠B=75°, and DB = 93 feet. Find the length of BC to the nearest tenth of a foot.

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adefunkeadewole adefunkeadewole
  • 14-03-2021

Answer:

89.8 feet

Step-by-step explanation:

In ΔBCD, the measure of ∠D=90°, the measure of ∠B=75°, and DB = 93 feet. Find the length of BC to the nearest tenth of a foot.

We would solve the above question using Sine rule

The formula is given as:

DB/sin D = BC/sin B

93/sin 90 = BC/sin 75

We cross multiply

sin 90 × BC = 93 × sin 75

BC = 93 × sin 75/sin 90

BC = 89.83 feet

Approximately BC = 89.8 feet

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