Answer:
[tex]tan(\frac{-11\pi}{6})= tan (-\pi +\frac{-5\pi}{6})\\\\ tan[-(\pi +\frac{5\pi}{6})]\\\\=-tan(\pi +\frac{5\pi}{6})\\\\=-(tan\frac{5\pi}{6})\\\\=-tan(\frac{5\pi}{6})\\\\=-tan(\pi -\frac{\pi}{6})\\\\=tan \frac{\pi}{6}\\\\ =\frac{1}{\sqrt{3}}[/tex]
