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  • 13-02-2021
  • Chemistry
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A ring of pure gold has a mass of 17.3 grams. How many atoms of gold are in the ring?

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octopods
octopods octopods
  • 13-02-2021

Answer:

5.29936 x 10^23 atoms

Explanation:

To do this, we need to find the number of moles in the ring so that we can then multiply that by Avogadro's number (6.022×10^23).

equation for finding moles: [tex]n = \frac{mass}{M_{r} }[/tex]

substitute in the known values: [tex]n = \frac{17.3}{197 }[/tex]

divide to find the value of n: 0.088 mol

Multiply by Avogadro's constant: 0.088 x 6.022 x 10^23

= 5.29936 x 10^23 atoms in the ring.

hope this helps!

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