narayanammaatluri
narayanammaatluri narayanammaatluri
  • 13-02-2021
  • Mathematics
contestada

Find the points which divide the line segment joining the points (0, -3) and (7,1) in the ratio 2:3
internally and externally

Respuesta :

cofuls
cofuls cofuls
  • 13-02-2021

Answer:

Known two points, list function expression, use

[tex]y-y_{0}=k(x-x_{0})[/tex]

[tex]k= \frac{y_{2} -y_{1\\}}{x_{2} -x_{1} }[/tex]

The function expression is

[tex]y=\frac{4}{7}x-3[/tex]

It is known that the cross section of two points is 7, so the point of 2:3 is 14 / 5, that is, 0 + 14 / 5 is the abscissa of the point, which is substituted into the original equation to get y = - 7 / 5.

So the result is   [tex](\frac{14}{5} ,-\frac{7}{5} )[/tex]

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