The volume of C₂H₂ : 28 L
Further explanation
Given
45g of water
Required
The volume of C₂H₂
Solution
Reaction
CaC₂(s) + 2 H₂O(l) ⇒ C₂H₂(g) + Ca(OH)₂(aq)
mol of water (MW = 18 g/mol) :
mol = mass : MW
mol = 45 g : 18 g/mol
mol = 2.5
From equation, mol ratio H₂O : C₂H₂ = 2 : 1, so mol C₂H₂ :
= 0.5 x mol H₂O
= 0.5 x 2.5
= 1.25
The volume of C₂H₂(assume at STP, 1 mol = 22.4 L) :
=1.25 mol x 22.4 L
=28 L
