Answer:
[tex]2.\:\frac{41}{9}[/tex]
Step-by-step explanation:
Recall that [tex]\frac{x}{9}=\lfloor \frac{x}{9} \rfloor + 0.\overline{[x\:\mod9]}[/tex].
Therefore, [tex]4.\bar{5}=\frac{4\cdot 9 + 5}{9}=\fbox{$2)\:\frac{41}{9}$}[/tex].
B is correct answer.................
