Answer:
[tex]x=2,\\x=-2,\\x=\sqrt{3},\\x=-\sqrt{3}[/tex]
Step-by-step explanation:
This is a quadratic in disguise. Let [tex]n=x^2[/tex]. We can rewrite the problem as a quadratic to solve:
[tex]n^2-7n+12=0,\\(n-3)(n-4)=0,\\n=3,\: n=4[/tex].
Now plug in these values of [tex]n[/tex] to solve:
[tex]\begin{cases}x^2=4, \:x=\pm 2\\\\x^2=3, x=\pm\sqrt{3}\end{cases}[/tex].
Therefore, our solutions are [tex]x=\pm 2, \:x=\pm\sqrt{3}[/tex].
