Answer:
Evaluating the piecewise function when X =3, we get f(3) = 7
Step-by-step explanation:
Given the following piecewise function
f(x)= { 2x+1; where x > 0
-3 when x ≤ 0
Evaluate the function when X = 3
We will evaluate f(x) =2x+1 where x > 0, because x = 3 and 3 <0
We can't use -3, because x ≤ 0, and 3 is not less than 0.
Now, evaluating the function:
[tex]f(x)=2x+1\\Put\:x=3\\f(3)=2(3)+1\\f(3)=6+1\\f(3)=7[/tex]
So, Evaluating the piecewise function when X =3, we get f(3) = 7
