Answer:
58.3%
Explanation:
The formula of the compound is given as:
CsPO₄
Now, the percentage composition of Cs in the compound is = ?
So;
To find this parameter, find the molar mass of the compound:
Molar mass of CsPO₄ = 132.9 + 31 + 4(16) = 227.9g/mol
Percentage composition of Cs= [tex]\frac{132.9}{227.9} x 100[/tex] = 58.3%
