Answer:
[g+2/3g-1] ÷ [g^2+2g/6g+2]
g+2/3g-1 × 6g+2/g^2+2g
g+2/3g-1 × 2(3g +1)/g(g+2)
1/ 3g-1 × 2(3g+1)/g
2(3g +1)÷ g(3g-1)
6g+2 ÷[3g^2-g]
