samsmamsndb samsmamsndb

13-01-2021
Mathematics

contestada

Two numbers differ by 5. The sum of their squares is 193. Find the numbers.

Respuesta :

ElizabethZi ElizabethZi

13-01-2021

Answer:

Let one number be x and the other be (x-5)

Step-by-step explanation:

x^2+(x-5)^2=193

x^2+x^2-10x+25=193

2x^2-10x+25=193

Subtract 193 from both sides of the equation.

2x^2-10x-168=0

x=12 or x=-7

x-5=7 or x-5=-12

Answer Link

Otras preguntas

y-1/x+3=-3/4 how do you solve for y

how to graph y=-4|x+2|-5

If Sean earns 8.50 per hour and made a total of 80.75 today,how many hours did he work?

If x is a real number such that x³ = 64, then x² + √x =?

How do I justify if these functions are inverses of each other ... F(x)=x^3 +4 & g(x)=3(radical sign) -4

If Sean earns 8.50 per hour and made a total of 80.75 today,how many hours did he work?

If Sean earns 8.50 per hour and made a total of 80.75 today,how many hours did he work?

The Rogers family drove a total of 482 miles, starting on Friday and ending on Sunday. They drove 138 miles on Friday and 225 miles on Saturday. How many miles

17. Which philosophy is evident in Monk Sewing attributed to Kao Ninga? Zen Pure Land Buddhism Shinto Daoism

y-1/x+3=-3/4 how do you solve for y