Given :
A polynomial [tex]3y^2 + ( y+7)^2 -15[/tex] .
To Find :
The polynomial after fully simplified and written in standard form.
Solution :
[tex]3y^2 + ( y^2 + (2)(7)(y) + 49 ) - 15[/tex] [ Using (a+b)² = a² + 2ab + b² ]
[tex]3y^2 + y^2 + 14y + 49 - 15\\\\4y^2 + 14y + 34\\\\[/tex]
Therefore, the equation of the polynomial in standard and simplified form is
[tex]4y^2 + 14y + 34\\\\[/tex]
