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13-01-2021
Mathematics

contestada

Find the zeros of f(x)= 2x^2 + 32
the zeros of f are x=_ & x=_

Respuesta :

13-01-2021

Answer:

[tex]2x^2+32=0\\2x^2=-32\\x^2=-16\\x=16i \\x=-16i[/tex]

are you completely sure you don't mean 2x^2-32? that would have real roots

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