Answer:
19.9 pF
Explanation:
Given that:
Series connection :
11pF and 21pF
C1 = 11pF ; C2 = 21pF
Cseries = (C1*C2)/ C1 + C2
Cseries = (11 * 21) / (11 + 21)
Cseries = 7.21875 pF
C1 = 22pF ; C2 = 30pF
Cseries = (C1*C2)/ C1 + C2
Cseries = (22 * 30) / (22 + 30)
Cseries = 12.6923 pF
Equivalent capacitance is in parallel, thus,
7.21875pF + 12.6923 pF = 19.91105 pF
= 19.9 pF
