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  • 16-12-2020
  • Mathematics
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need help solving #8

need help solving 8 class=

Respuesta :

carolmartelotte2020 carolmartelotte2020
  • 16-12-2020

Answer:

7)[tex]2^x=2^8x-15[/tex]

Apply exponents rules

[tex]x=8x-15[/tex]

Solve [tex]x=8x-15: x=\frac{15}{7} \\[/tex]

Answer: [tex]x=\frac{15}{7} \\[/tex]

8)[tex]4^x=2^x+1\\2x=x+1\\x=1[/tex]

Answer : [tex]x=1[/tex]

9)[tex]5^x+3=7^x\\(x+3) in (5)=xln(7)\\x=\frac{3ln(5)}{in(7)-in(5)}[/tex]

Answer: [tex]x=\frac{3ln(5)}{in(7) -in(5)}[/tex]

Step-by-step explanation:  

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