Answer:
(C). The magnitude of electric force acting on the raindrop is 0.1 N.
Explanation:
Given;
charge of the raindrop, Q = 10 μC = 10 x 10⁻⁶ C
electric field strength, E = 10,000 V/m
The electric force acting on the raindrop is given as;
F = EQ
where;
F is the electric force
Substitute the given values and solve for F.
F = (10,000)(10 x 10⁻⁶)
F = 0.1 N
Therefore, the magnitude of electric force acting on the raindrop is 0.1 N.
