Respuesta :

emiyahtjones2005
Let A=the remaining amount of radium
Let S=the amount of radium you start with
Let t=the amount of time in years
Let h=the half-life time

Then A=S(1/2)^(t/h)
So,
A=80(1/2)^(430/1690)
A=approx. 67g

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