Answer:
4c^2 - 3a^2 -7ac +6bc -ab
Step-by-step explanation:
solve first 3a( a + b + c) - 2b ( a+ b +c)
which is = 3a^2 + 3ab + 3ac - 2ab - 2b^2 -2bc
there for 4c(-a + b +c) -( 3a^2 + 3ab + 3ac - 2ab - 2b^2 - 2bc)
= -4ac-3ac +4bc+2bc -3ab+2ab + 4c^2 -3a^2
=4c^2 - 3a^2 -7ac +6bc -ab
