Answer:
x=50°
Angle at A=108°
Step-by-step explanation:
If the triangle ABC is isosceles,then <ABC=<ACB=65°
We can now use angle properties to find <BAC
<BAC+65+65=180°
<BAC=180°-130=50°
Since line AB and CD are parallel,line AC is a transversal line which means <BAC=<ACD=x=50°
Therefore x=50°
For the parallelogram,
opposite interior angles are equal so <BAD=<BCD and <ABC=<ADC
3x+3x+2x+2x=360°
10x=360°
x=360°/10=36°
The angle at a=3x=3×36°=108°
