kels7Sil1vachieaux
kels7Sil1vachieaux kels7Sil1vachieaux
  • 14-10-2016
  • Mathematics
contestada

What is the 25th term of the arithmetic sequence where a1=8 and a9=48 ? answers to choose from. a)113. b)118. c)123. d)128

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Lampa20
Lampa20 Lampa20
  • 18-10-2016
First we need to find "d" which is difference between any 2 successive members of the sequence. Because the sequence is arithmetic that means that the difference between any 2 successive members is same and constant.

This is the formula for any member of sequence at position "n"
An = A1 + (n-1)*d
d = (a9 - a1)/(9-1)
d = 5

Now we calculate 25th member:
a25 = a1 + (25-1)*5
a25 = 128

Answer is d)
Answer Link
diya2000hamed diya2000hamed
  • 07-01-2020

Answer:

128

Step-by-step explanation:

Answer Link

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