Answer:
[tex]\huge\boxed{8x=64}[/tex]
Step-by-step explanation:
[tex]-\dfrac{1}{2}x+5=1\qquad|\text{subtract 5 from both sides}\\\\-\dfrac{1}{2}x+5-5=1-5\\\\-\dfrac{1}{2}x=-4\qquad|\text{multiply both sides by (-2)}\\\\(-2\!\!\!\!\diagup)\cdot\left(-\dfrac{1}{2\!\!\!\!\diagup}x\right)=(-2)(-4)\\\\x=8\qquad|\text{multiply both sides by 8}\\\\8\cdot x=8\cdot 8\\\\8x=64[/tex]
