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  • 12-10-2020
  • Mathematics
contestada

Write an equation of the parabola in vertex form that passes through (13,8) and has vertex (3,2).

Respuesta :

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  • 12-10-2020

Answer:

[tex]y=\frac{3}{50} (x-3)^{2}+2[/tex]

Step-by-step explanation:

Vertex: (3,2)

Point: (13,8)

The equation form is [tex]y=a(x-h)^2+k[/tex]

h = 3

k = 2

y = 8

x = 13

Plug in the values into the form..

[tex]8=a(13-3)^{2} +2[/tex]

Simplify and solve for a..

[tex]8=a(10)^{2}+2[/tex]

[tex]8=100a+2[/tex]

[tex]100a=8-2[/tex]

[tex]100a=6[/tex]

[tex]a=\frac{6}{100} or \frac{3}{50}[/tex]

Plug a into the equation..

[tex]y=\frac{3}{50} (x-3)^{2}+2[/tex]

Hope this helped you!

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