Answer:
h =12
Step-by-step explanation:
[tex]In\: \triangle ABC, \: \angle ABC = 90\degree \: \&\:\\ BD\perp AC[/tex]
Therefore, by geometric mean property:
[tex]BD = \sqrt {AD\times CD} \\
h = \sqrt {(AC-CD) \times CD} \\
h = \sqrt {(25-16) \times 16} \\
h = \sqrt {9 \times 16} \\
h = \sqrt {144} \\
\huge \red {\boxed {h = 12}} \\
[/tex]
