Answer:
244 moles of phosphorus are present in 61.0 moles of [tex]P_4O_{10}[/tex].
Explanation:
Moles of [tex]P_4O_{10}[/tex] = 61.0 moles
1 mol of [tex]P_4O_{10}[/tex] contains 4 moles of phosphorus.
Then 61.0 moles of [tex]P_4O_{10}[/tex] will contain:
[tex]61.0 mol\times 4=244 mol[/tex] of phosphorus
244 moles of phosphorus are present in 61.0 moles of [tex]P_4O_{10}[/tex].
