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  • 15-09-2016
  • Chemistry
contestada

0.01800 kg of mercury (hg) occupies a volume of 1.325ml at 4oc. calculate the density of hg in grams per milliliter at this temperature.

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Willchemistry
Willchemistry Willchemistry
  • 15-09-2016
0.01800 kg x 1000 => 18.0 g 

D = m / V

D = 18.0 / 1.325

D = 13.58 g/mL

hope this helps!
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