Answer:
C₆H₁₅O₃N + H₂O ⇄ C₆H₁₅O₃NH⁺ + OH⁻
Explanation:
A Bronsted-Lowry base is defined as a substance than can accept a proton, H⁺.
When triethanolamine, C₆H₁₅O₃N, reacts with water, H₂O, as follows:
C₆H₁₅O₃N + H₂O ⇄ C₆H₁₅O₃NH⁺ + OH⁻
As you can see, in this reaction, triethanolamine is able to accept a proton that is given for the water.
