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13-09-2020
Mathematics

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Find two consecutive odd integers such that seven times the first equals five times the second.

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13-09-2020

Answer:

Odd integers are always one more that an even integer:

1st: 2n+1

2nd: 2n+3

Step-by-step explanation:

14n+7 = 10n+15

4n = 8

n = 2

------------

1st: 2n+1 = 5

2nd: 2n+3 = 7

7x=5*(x+2)

7x=5x+10

7x-5x=10

2x=10

x=5

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