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12-09-2020
Mathematics

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12-09-2020

Since PQ = QR = RS,

Let's set PQ equal to RS

2x + 3 = x + 10

Subtract x and 3 from both sides.

x = 7

PQ = 2x + 3 = 2(7) + 3 = 14 + 3 = 17

Since PQ = QR = RS,

QR = 17

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