Answer:
0.083 V
Explanation:
The equation of the reaction is;
Pb(s) + 2H^+(aq) -------> Pb^2+(aq) + H2(g)
E°cell = E°cathode - E°anode
E°cathode = 0.00 V
E°anode = -0.13 V
E°cell = 0.00-(-0.13)
E°cell = 0.13 V
Q= [Pb^2+] pH2/[H^+]^2
Q= 0.1 × 1/[0.05]^2
Q= 0.1/0.0025
Q= 40
From Nernst's equation;
Ecell= E°cell- 0.0592/n log Q
Ecell= 0.13 - 0.0592/2 log (40)
Ecell = 0.13 - 0.047
Ecell= 0.083 V
