Answer:
0.0107
Explanation:
We know that
The rotational kinetic energy due to four wheel is
1/2ဃ²I x 4
So
1/4mR²(v/R)² = mv²
But kinetic energy along straight path of the car is 1/2mv²
=> 1/2( 817)v ²
Kc= 408.5v²
So The fraction of total kinetic energy that is due to rotation of the wheel about their axis
Is Kw/Kw+Kc
and Kw = 1/2* 8.91v²= 4.45v²
So 4.45v²/ 4.45v²+ 408.5v²
= 0.0107 as fraction of total kinetic energy
