Answer:
[tex] {x}^{2} + 0x + 1[/tex]
Step-by-step explanation:
[tex]for \: g (fx) \:the \: function \: of \: f \: is \: inserted \: into \: the \: x \: for \: the \: g[/tex]
So the eqn becomes
[tex] ({x}^{2} - 1) + 2[/tex]
AND this equal to
[tex] {x}^{2} + 1[/tex]
Hence the variable x has 0 as its coefficient.
