Answer:
Step-by-step explanation:
Let's start with the first rectangle with a lenght of 3c+2
- let A1 be the area of that rectangle :
- A1= (3c+2)*2c
Now the second rectangle :
- Let A2 be the area of that triangle :
- A2= (3c+2-(2c+2))*(3c-2c)
- A2= (3c+2-2c-2)*c
- A2= c*c
Let At be the total area :
- At= (6c²+4c)*c² = (6c∧4 +4c³ )
