Respuesta :

tramserran

Answer:   x < 3

Step-by-step explanation:

4(x + 3) < 3(x + 5)

4x + 12 < 3x + 15           Distributed

 x + 12 < 15                   Subtracted 3x from both sides

       x  < 3                     Subtracted 12 from both sides

ensiah193

Answer:

4x^2+9x-15<0

Step-by-step explanation:

x.4(x+3)<3(x+5)

(4x)(x+3)<3x+3x5

(4x)(x+3)<3x+15

4xx+4x.3<3x+15

4x^1+1+4x3x<3x+15

4x^2+12x<3x+15

(4x^2+12x)+(-3x-15)<(3x+15)+(-3x-15x)

4x^2+9x-15<3x-3x+15-15

4x^2+9x-15<0